Friday, June 24, 2016

thermodynamics - Joule Thomson Coefficient derivation


In deriving Joule Thomson effect coefficient, why do we take $dH=0$ and also why do we take $H$ as a function of $T$ and $P$ only and not $V$? i.e. why do we take $$(\partial H/ \partial T)dT+(\partial H/\partial P)dP=0$$ and not


$$(\partial H/\partial T)dT+(\partial H/\partial P)dP+(\partial H/\partial V)dV=0$$


Any links would also be appreciated.


Thanks.




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