Let us say that I apply a non-unitary transformation $\def\ket#1{| #1\rangle} \def\braket#1#2{\langle #1|#2\rangle} \hat A$ to the ket's: $$\ket{\psi} \rightarrow \hat A \ket{\psi}$$ $$\ket{\phi}\rightarrow \hat A \ket{\phi}$$ Clearly in this case the probability: $$P=|\braket{\phi}{\psi}|^2$$ Will change. What physically is going on here? i.e. why for unitary operators we can perform such a transformation but for non-unitary operators we can't?
Subscribe to:
Post Comments (Atom)
classical mechanics - Moment of a force about a given axis (Torque) - Scalar or vectorial?
I am studying Statics and saw that: The moment of a force about a given axis (or Torque) is defined by the equation: $M_X = (\vec r \times \...
-
In the crystal, infinitesimal translational symmetry breaking makes the phonon, In ferromagnet, time-reversal symmetry breaking makes magnon...
-
A "Schrödinger's cat state" is a macroscopic superposition state. Quantum states can interfere in simple experiments (such as ...
-
The degeneracy for an $p$-dimensional quantum harmonic oscillator is given by [ 1 ] as $$g(n,p) = \frac{(n+p-1)!}{n!(p-1)!}$$ The $g$ is the...
No comments:
Post a Comment