Problem: A plank of length $L$ and mass $m$ lies on a frictionless floor, if the plank has an initial velocity $v$, what is the stopping time of the block if it meets a floor with friction constant $\mu$.
My attempt:
I took a little piece of block with mass $\Delta m$, we know that $\Delta m = m\frac{\Delta \ell}{L}$.
Now if I apply the Newton laws in this piece, I get the following equation:
$$N_{piece}= \Delta mg $$
Thus my friction is $f_r=\mu\Delta mg$
If I apply Newton laws to the whole plank, I get:
$$-f_r=ma$$ $$\mu\Delta mg=ma$$ $$\mu mg\frac{\Delta \ell}{L}=ma$$
$$a=\mu g\frac{\Delta \ell}{L}$$
I have this equation, but I don't know how to relate it with time.
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