iℏdUI(t,ti)dt=ˆVI(t)ˆUI(t,ti) The solutions of this equation, with the initial condition ˆUI(ti,ti), are given by the integral equation ˆUI(t,ti)=1−iℏ∫ttiˆVI(t′)ˆUI(t′,ti)dt′
In the derivation of Dyson Series please explain why in equation (10.33) t is changed to t′ without integrating.
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