Sunday, August 30, 2015

quantum mechanics - Difference between |0rangle and 0 in the context of isospin


I know this has been asked before, but I am confused having read it in the context of isospin, where the creation operators act on the "vacuum" state (representing no particles) am|0=|m

to create nucleon labelled by m (m can be proton/neutron). And the action of annihilation operator is a|0=0
As |0 was already the vacuum state with no particles, what exactly did the annihilator annihilate?



In the linked question, I could understand David's and Ted's answer in the context of the Harmonic oscillator, angular momentum and such. But in this case, it is hard to imagine |0 as a normalized non-zero vector , which does not contain anything whose energy is not zero.



Answer



The state |0 is not the zero vector in Hilbert space, it is a state containing no physical excitations. Since the Harmonic oscillator was not enough, perhaps you can understand this as follows.


Let me make a box with mirrors, and then prepare the following state


|ψ=12|0+12|k


This state is a superposition of the state with no-photons in the box, and the state with one photon in the box with wavenumber k. Now take the expected value of the number-of-photons operator in this state, using the number operator N, given by:


N=kakak


ψ|N|ψ


The vacuum part gives 1/2 of zero, while the k-part gives 1/2 of 1. So the expected number of particles is 1/2, and this requires that the state |0 be annihilated by the annihilation operator--- that it must have eigenvalue 0, that it must go to the zero vector. The interpretation is that there is a probability 1/2 of zero particles, and a probability 1/2 of 1 particle, so the expected average number of particles is 1/2.


This example is to show why the state |0, the state where there are zero particles, is an ordinary unit-length state. It can exist in superpositions with other states.



No comments:

Post a Comment

classical mechanics - Moment of a force about a given axis (Torque) - Scalar or vectorial?

I am studying Statics and saw that: The moment of a force about a given axis (or Torque) is defined by the equation: $M_X = (\vec r \times \...