Suppose we have object A , which has momentum mv. Then it elastically collides with a wall, so it's momentum now -mv, So how is momentum conserved here ?
Answer
object A has it's momentum change by ΔpA=−2mAvA. This means that the wall must gain momentum Δpwall=+2mAvA. To conserve momentum. We can calculate the change in velocity of the wall now. Δvwall=Δpwall/mwall=+2mAmwallvA. The point here is that the mass of the wall us much greater than the mass of the object mwall≫mA. so we basically treat Δvwall as being zero. This is why there is an apparent breaking of conservation of momentum, but as you can see, if you take into account the momentum of the wall you'll see momentum is conserved.
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