The wave is
ˉE=E0sin(2πzλ+wt)ˉi+E0cos(2πzλ+wt)ˉj
Let's simplify with z=1. Now the xy-axis is defined by parametrization (sin(2πλ+wt),cos(2πλ+wt) where t is time and λ is wavelength. This parametrization satisfy the equation 12=x2+y2, a circle.
Now, let's variate the value of z. We know now that it cannot move into x or y coordinates or do we? Not really, the latter simplification is naive -- x−y parametrization depends on the dimension z -- but can we see something from it? If so, how to proceed now?
The solution is that the wave moves along the z -axis to the negative direction as t increases, a thing I cannot see.
The way I am trying to solve this kind of problems is:
- Parametrize the equation
- suppose other things constant and change one dimension, observe
- check other variable
...now however I find it hard to parametrize the z so a bit lost. So how can I visualize the wave with pen-and-paper?
Answer
Would you agree that →E depends only on 2πzλ+ωt (taking E0 to be a constant)?
If so, we can imagine picking some spot it space and time, taking note of the value of →E at that point and looking to see how we have to move to keep the value constant in time
2πzλ+ωt=C
where C is determined entirely by our initial choice of space--time location. So:
z=z(t)=λ2π(C−ωt)
represents a locus of z-positions as a function of time where →E continues to have the same value it had at our starting point. And those positions move in the negative z direction as time increases.
Question for the studuent: how fast do they move?
You should be able to answer by inspection.
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