Monday, July 11, 2016

classical mechanics - How do non-conservative forces affect Lagrange equations?


If we have a system and we know all the degrees of freedom, we can find the Lagrangian of the dynamical system. What happens if we apply some non-conservative forces in the system? I mean how to deal with the Lagrangian, if we get any external non-conservative forces perturbs the system?


Example:


We have a mass m that is attached with a massless spring.


We could write the Lagrangian as L=12m˙x2+mgx12kx2.


What happens to this equation if we consider any non-conservative forces?



Answer



More generally, Lagrange equations1 read


ddt(TU)˙qj(TU)qj = QjF˙qj+m=1λaj,j {1,,n},



where




  • q1,,qn, are n generalized position coordinates;




  • T is the kinetic energy;




  • U is a generalized potential;





  • F is the Rayleigh dissipation function for friction forces;




  • Q1,,Qn, are the remaining parts of the generalized forces, which are not described by the generalized potential U or the Rayleigh dissipation function F;




  • λ1,,λm, are m Lagrange multipliers for m semi-holonomic constraints nj=1aj(q,t)˙qj+at(q,t) = 0, {1,,m}. One may think of the last term on the right-hand side of eq. (L) as the generalized constraint forces for the semi-holonomic constraints (SHC). All other constraints are assumed to be holonomic.





For a discussion of conservative & non-conservative forces, see also e.g. this Phys.SE post.


References:



  1. H. Goldstein, Classical Mechanics; Chapter 1 & 2.


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1 We distinguish between Lagrange equations (L) and Euler-Lagrange equations ddtL˙qjLqj = 0,j {1,,n}. In contrast to the Lagrange equations (L), the EL equations are by definition always assumed to be derived from a stationary action principle. We should stress that it is not possible to apply the stationary action principle to derive the Lagrange equations (L) unless all generalized forces have generalized potentials U. See also e.g. this and this Phys.SE posts.


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