Why is the angle of a wake of a duck constant? And why are some conditions on the water depth necessary?
I realize that this question turns up in google searches, but I did not see a good discussion. I will be quite happy with a link.
Edited to add:
Could anyone tell me how the two up-voted answers are related?
Answer
The ideal Kelvin boat wake ignores surface tension, and it assumes deep water waves with an (in general) broad spectrum of frequencies ω with dispersion relation ω2=gk, where g≈9.8ms2. The ideal Kelvin wake furthermore assumes that the ship sails with a constant velocity, and that the wave amplitudes of the partial waves are so small that they obey a linear superposition principle. The Kelvin wake does not describe the narrow turbulent band behind a ship, nor shock waves. The Kelvin wake consists of two types of waves: transverse and divergent waves. There are two characteristic angles
α≈19∘andβ≈35∘,
corresponding to
tan(α)=12√2andtan(β)=1√2,
or equivalently,
sin(α)=13andsin(β)=1√3.
In polar coordinates (r,θ) of a co-moving coordinate system, where the position of the boat is at the origin, the transverse waves are in the region |θ|≤β, and divergent waves are in the region α≤|θ|≤β.
The angles α and β are constant in at least two ways: Firstly, they don't depend on the distance r to the ship. This is because the speed of each partial wave (with frequency ω) is independent of the position (x,y). Secondly, α and β are, evidently, universal angles, independent of, for instance, g. This is explained in the references below.
(source: wikiwaves.org)
References:
1) Howard Georgi, "The Physics of Waves", Chapter 14. (Hat tip:user1631.)
2) MIT on-line open course ware, mechanical engineering, wave propagation, lecture notes, fall 2006, Chapter 4.7.
3) Wikiwaves.
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