We say that when the thermal de Broglie wavelength is much smaller than the interparticle distance, the gas can be considered to be a classical or Maxwell–Boltzmann gas. On the other hand, when the thermal de Broglie wavelength is on the order of or larger than the interparticle distance, quantum effects will dominate and the gas must be treated as a Fermi gas or a Bose gas, depending on the nature of the gas particles. $(V/N)^{1/3} < \lambda_{th} $. My question is why do quantum effects dominate?
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classical mechanics - Moment of a force about a given axis (Torque) - Scalar or vectorial?
I am studying Statics and saw that: The moment of a force about a given axis (or Torque) is defined by the equation: $M_X = (\vec r \times \...
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In the crystal, infinitesimal translational symmetry breaking makes the phonon, In ferromagnet, time-reversal symmetry breaking makes magnon...
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A "Schrödinger's cat state" is a macroscopic superposition state. Quantum states can interfere in simple experiments (such as ...
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The degeneracy for an $p$-dimensional quantum harmonic oscillator is given by [ 1 ] as $$g(n,p) = \frac{(n+p-1)!}{n!(p-1)!}$$ The $g$ is the...
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