I was wondering about the following:
If you have the time-dependent Schrödinger equation such that iℏ∂ψ(x,t)∂t=−ℏ22m∂2ψ(x,t)∂x2+V(x,t)ψ(x,t),
where the potential is also time dependent. What is the general strategy to solve this one? Separation of Variables or are there better techniques available? Especially if V(x,t)=V1(t)V2(x). For example if you know the solution to En=−ℏ22m∂2ψ(x,t)∂x2+V2(x)ψ(x),
Answer
Firstly, there are a few issues with a time-dependent potential, V(x,t). Namely, if we apply Noether's theorem, the conservation of energy may not apply. Specifically, if under a translation,
t→t+t′
the Lagrangian L=T−V(x,t) changes by no more than a total derivative, then conservation of energy will apply, but this resricts the possible V(x,t), depending on the system.
We often treat each Schrödinger equation case by case, as a certain system may lend itself to a different approach, e.g. the harmonic oscillator is easily solved by employing the formalism of creation and annihilation operators. If we consider a time-dependent potential, the equation is generally given by,
iℏ∂ψ∂t=−ℏ22m∂2ψ∂x2+V(x,t)ψ
Depending on V, the Laplace or Fourier transform may be employed. Another approach, as mentioned by Jonas, is perturbation theory, whereby we approximate the system as a simpler system, and compute higher order approximations to the fully perturbed system.
Example
As an example, consider the case V(x,t)=δ(t), in which case the Schrödinger equation becomes,
iℏ∂ψ∂t=−ℏ22m∂2ψ∂x2+δ(t)ψ
We can take the Fourier transform with respect to t, rather than x, to enter angular frequency space:
−ℏωΨ(ω,x)=−ℏ22mΨ″(ω,x)+ψ(0,x)
which, if the initial conditions are known, is a potentially simple second order differential equation, which one can then apply the inverse Fourier transform to the solution.
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