Thursday, April 16, 2015

quantum mechanics - Time-dependent Schrödinger equation with V=V(x,t)


I was wondering about the following:


If you have the time-dependent Schrödinger equation such that iψ(x,t)t=22m2ψ(x,t)x2+V(x,t)ψ(x,t),


where the potential is also time dependent. What is the general strategy to solve this one? Separation of Variables or are there better techniques available? Especially if V(x,t)=V1(t)V2(x). For example if you know the solution to En=22m2ψ(x,t)x2+V2(x)ψ(x),

does this help to find the general solution?



Answer



Firstly, there are a few issues with a time-dependent potential, V(x,t). Namely, if we apply Noether's theorem, the conservation of energy may not apply. Specifically, if under a translation,


tt+t


the Lagrangian L=TV(x,t) changes by no more than a total derivative, then conservation of energy will apply, but this resricts the possible V(x,t), depending on the system.




We often treat each Schrödinger equation case by case, as a certain system may lend itself to a different approach, e.g. the harmonic oscillator is easily solved by employing the formalism of creation and annihilation operators. If we consider a time-dependent potential, the equation is generally given by,



iψt=22m2ψx2+V(x,t)ψ


Depending on V, the Laplace or Fourier transform may be employed. Another approach, as mentioned by Jonas, is perturbation theory, whereby we approximate the system as a simpler system, and compute higher order approximations to the fully perturbed system.




Example


As an example, consider the case V(x,t)=δ(t), in which case the Schrödinger equation becomes,


iψt=22m2ψx2+δ(t)ψ


We can take the Fourier transform with respect to t, rather than x, to enter angular frequency space:


ωΨ(ω,x)=22mΨ(ω,x)+ψ(0,x)


which, if the initial conditions are known, is a potentially simple second order differential equation, which one can then apply the inverse Fourier transform to the solution.


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