Does anyone have an intuitive explanation of why this is the case?
Answer
This is a note on why angular velocities are vectors, to complement Matt and David's excellent explanations of why rotations are not.
When we say something has a certain angular velocity $\vec{\omega_1}$, we mean that each part of the thing has a position-dependent velocity
$\vec{v_1}(\vec{r}) = \vec{\omega_1} \times \vec{r}$.
We might consider another one of these motions
$\vec{v_2}(\vec{r}) = \vec{\omega_2} \times \vec{r}$
and wonder what happens when we add them. We get
$\vec{v_1}(\vec{r}) + \vec{v_2}(\vec{r}) = \vec{\omega_1} \times \vec{r} + \vec{\omega_2} \times \vec{r}$.
The cross product is linear, so this is equivalent to
$(\vec{v_1} + \vec{v_2})(\vec{r}) = (\vec{\omega_1} + \vec{\omega_2}) \times \vec{r}$,
so it makes fine sense to add angular velocities by vector addition.
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