mathematics - Make numbers 93 using the digits 2, 0, 1, 8

I have a 1 to 100 building challenge with 2, 0, 1, 8, all made but 93 is not made. I need your help!

This is similar to the "Four fours" puzzle, but using the digits 2, 0, 1 and 8.

Rules:

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  Use all four digits exactly once

  
  


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  Allowed operations: +, -, x, ÷, ! (factorial), exponentiation, square root Parentheses and grouping (e.g. "21") are also allowed

  
  


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  Squaring uses the digit 2 so expressions using multiple twos, like 2222 or 12+8212+82, are not allowed

  
  


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  Multi-digit numbers and decimal points can be used such as 20, 102, .02 but you CANNOT make 30 by combining (2+1)0

  
  


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  Recurring decimals can be used using the '

  
  
  

For example :

.2' = 0.222222.....

.12' = 0.1222222.....

.1'2' = 0.12121212.....

Answer

I think this is valid by your rules :

$ .1^{-2} - 8 + 0! $

$= 100 - 8 + 1 $
$ = 93 $