Wednesday, May 22, 2019

quantum field theory - Why is there sometimes an additional term in the orthogonality relations for the polarization vectors?


When considering the polarization vectors of a massive spin-1 field, like an Aμ with Lagrangian density L=14FμνFμν+12M2AμAμ,

we expand the solutions of Aμ as Aμ(x)=λd˜k[εμ(λ,k)a(λ,k)eikx+εμ(λ,k)a(λ,k)eikx],
where the three polarization vectors {ε(λ,k)}λ satisfy the completeness relations λεμ(λ,k)εν(λ,k)=ημν+kμkνM2.


The questions:



  1. Where does the second term kμkν/M2 come from?


  2. Why is it needed?

  3. Using (C) and going to the massless M0 limit we get a singularity, which would make the relation ill defined. So how should the massless limit be handled?

  4. In what other circumstances (massive/massless spin-X fields) is a similar correction to the completeness relations needed?




The above formulas can be found for example in Srednicki, (85.16), with a somewhat different notation (he uses opposite Minkowski space metric convention than me).



Answer





  1. Observe that the "completeness" relation is just the projector onto the space spanned by the polarisation vectors. A priori, we know that Pμνϵ:=λϵμλ(k)ϵνλ(k) therefore projects onto the subspace orthogonal to the momentum, since ζμkμ=0 for any polarization vector ζμ. The most general symmetric 2-tensor depending on only the metric and the momentum is Pμνϵ=aημν+bkμkν with a,bC initially arbitrary. Applying the projector to the momentum yields Pμνϵkμ=akν+bk2kν!=0, and using k2=m2, the relation you quote is obtained.





  2. Because it is the condition that the vector is a polarization, and not any vector.




  3. The massless limit of the Proca action is indeed ill-defined. One can use the Stückelberg Lagrangian with an auxiliary scalar field ϕ, which has a smooth massless limit as well as explicit gauge invariance for massive U(1) fields. (This is why massive photons are not a problem in QED)




L=14FμνFμν+12(μϕ+mAμ)(μϕ+mAμ)




  1. You need such a modification every time you have unphysical degrees of freedom, as we have with polarizations k in this case.


No comments:

Post a Comment

classical mechanics - Moment of a force about a given axis (Torque) - Scalar or vectorial?

I am studying Statics and saw that: The moment of a force about a given axis (or Torque) is defined by the equation: $M_X = (\vec r \times \...