Friday, May 17, 2019

Why is force a localized vector and not a free vector?



A vector which is drawn parallel to a given vector through a specified point unlike free vector in space is called a localised vector. The effect of a force acting on a body depends not only on the magnitude & direction but also on its point of application & line of action.




What is localized vector and how is force a localized vector? Can anyone clarify me the book's reasoning?



Another property of the force is that the point of application of a given force acting on a rigid body may be transferred to any other point on the line of action without altering the effect of the force.



What is this all about? I couldn't understand this property infact the whole para. What does the book talk about force in this para? Plz help clarifying the meanings.



Answer



A force is a vector acting along a line in space. It may act anywhere along the line and the end result will be the same (2nd paragraph).


The reason pure forces act on lines is that if they move away from the line there will be a torque applied also and the resulting motion will not be the same. The line of action of a force is the locus of the point where no net torque exists for this force.


Given a set of forces and torques specified at an arbitrary point, the location (and direction) of the line of action can be found. This line is unique, meaning that only one exists for each set of force and torque components.



In addition, these principles are dual to the idea of rotations about axes. Rotational motion needs to have the location of the rotation axis specified to be fully defined. Any other point away from the rotation axis will exhibit linear motion.


To fully specify the loading on a rigid body you need one of these two pieces of information:



  • A force vector $\vec{F}$ and a point which the line of action goes through $\vec{r}$. The equivalent torque at the origin is $\vec{\tau}=\vec{r} \times \vec{F}$.

  • A force vector $\vec{F}$ and the equivalent torque at the origin $\vec{\tau}$. The location of the line of action closest to the origin is $\vec{r} = \frac{\vec{F}\times \vec{\tau}}{\|\vec{F}\|^2}$.


To fully specify the motion of a rigid body you need one of these two pieces of information:



  • The rotation vector $\vec{\omega}$ and a point which the rotation axis goes through $\vec{r}$. The linear velocity at the origin is $\vec{v}=\vec{r} \times \vec{\omega}$.

  • The rotation vector $\vec{\omega}$ and the linear velocity at the origin $\vec{v}$. The location of the rotation axis closest to the origin is $\vec{r} = \frac{\vec{\omega}\times \vec{v}}{\|\vec{\omega}\|^2}$.



Quantities that require one free vector and one line vector to fully specify something are called screws (or screw vectors). All screws transform from one place to another with the same laws. Some quantities that are screws are:



  • Small motions (infinitesimal movement)

  • Rigid Body Motion (velocity)

  • Momenta (linear and angular)

  • Impulses and Contacts

  • Forces & torques

  • Spatial Acceleration (motion of entire rigid body)



Quantities that are not screws are:



  • Body Rotations (large angles are not vectors)

  • Material Accelerations (motion of each particle on a body)


Note $\times$ is the vector cross product, and $\cdot$ the vector dot product


No comments:

Post a Comment

classical mechanics - Moment of a force about a given axis (Torque) - Scalar or vectorial?

I am studying Statics and saw that: The moment of a force about a given axis (or Torque) is defined by the equation: $M_X = (\vec r \times \...