electrostatics - Electric field and Gauss law

If we take a Gauss surface S to calculate the electric field using Gauss law: $$\int\epsilon\vec{E}.\vec{dS}=\sum(Q's\ inside\ S\ + Q's\ on\ S\over2 )$$

then this field calculated $E$ is for what?Is this $E$ for each point(individually) on Gauss surface taken only i.e. do we mean by this E the electric field done due to the charges covered by the Gauss surface taken,done on each unique point on Gauss surface chosen?or is it also for points inside the surface?(short answer)