In relativity, the symmetric energy-momentum tensor is given by Tij,
where T00 is the energy density and 1cT10 is the momentum density. Thus: (1cT00dV,1cT10dV)T
is the 4-momentum. Under a Lorentz transformation, this should transform like 4-vectors where 1cT00dV=[1cT′00dV′+vc2T′10dV′](1−v2c2)−1/2dV=dV′√1−v2c2.
After simplifications, we have: T00=[T′00+vcT′10](1−v2c2)−1
But if we apply the Lorentz transformation to the tensor directly we get T00=[T′00+vcT′10+v2c2T 11](1−v2c2)−1
What accounts for the difference? I think the first is wrong but have no idea why.
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