Wednesday, December 28, 2016

lagrangian formalism - Conjugate Momenta in a Supersymmetric Sigma Model


Consider the following theory comprising of n bosons and n fermions (along with their conjugates) on a Riemannian Manifold, with arc length parameter t (section 10.4.1, Mirror Symmetry by Vafa et al.):L=12gij˙ϕi˙ϕj+i2gij(ˉψiDtψjDtˉψiψj)14Rijklψiψjˉψkˉψl

with the fermion covariant derivative:Dtψi=tψi+˙ϕjΓijkψk
I am having a problem deriving the following conjugate momenta for ϕi and ψm:pm=L˙ϕm=gmj˙ϕj
πψm=igmjˉψj
Here are the details of the issues that I'm having:


Problem: From the fact that the momentum conjugate to ˉψi has not been given, I deduce that it must be zero, so I try to use an integration by parts to absorb the two terms enclosed within the brackets in (1) in to one single term. The result is the following Lagrangian:L=12gij˙ϕi˙ϕj+igijˉψiDtψj14Rijklψiψjˉψkˉψl

Inflicting the partial derivatives I get the following result:πψm=L˙ψm=igmjˉψj
πˉψm=L˙ˉψm=0
So far I have the fermionic momenta correct. The issue arises when I try to compute the bosonic momentum:pm=L˙ϕm=gmj˙ϕj+iΓjkmˉψjψk
Clearly there is an additional non vanishing term which makes (8) differ from (3). Alternatively, should we (leaving aside the fermionic momenta for a while) work with (1) thinking that two such terms may cancel, we get:pm=L˙ϕm=gmj˙ϕj+i2(jgkmkgjm)ˉψkψj
Again this is non vanishing term. Is the fermionic covariant derivative to be treated independent of ˙ϕm so that it is killed by the derivative operator ˙ϕm? Or is (3) a typing error? Or is it something else? Kindly help out.



Answer





  • Yes, OP's eq. (8) for the canonical momentum is correct while eq. (3) is indeed an typo on the top of p. 208 in Ref. 1. See also point 6 in my Phys.SE answer here.





  • Calculating the fermionic canonical momentum is subtle for reasons mention in point 2 of the same answer.




References:



  1. K. Hori, S. Katz, A. Klemm, R. Pandharipande, R. Thomas, C. Vafa, R. Vakil, and E. Zaslow, Mirror Symmetry, 2003. The PDF file is available here.


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