If I put next to my cooler another similar cooler that produces similar white noise, will the overall noise level increase?
I want to point out that I am speaking about adding another independent, non-correlated white noise source, not just another pair of speakers that produce sound of the same phase and curve. It is evident for me that adding another speaker will increase amplitude twofold compared to one speaker, but this is not evident for coolers which produce non-correlated sound.
Answer
I assume you're talking about "coolers" as in CPU-coolers or other cooling systems in computers. The noise-spectrum from such a fan is not white strictly speaking, you can see it measured on this page. The spectrum is fairly level if you look at small parts though and ignore the tonal components.
Anyway, by your definition, two uncorrelated white noise sources add without interference. The "peaks and troughs" (sound pressures) don't add up coherently (in ideal sources of course :), but they don't cancel each other perfectly either. Therefore the sound power is doubled. By definition the RMS-amplitude (proportional to the sound pressure) is then multiplied by $\sqrt 2$. The sound intensity is proportional to the sound power and hence is doubled as well.
I actually simulated this in Matlab, because the terminology with sound power, sound energy, sound levels, sound pressures etc is daunting, misleading and confusing.. I'm specifically avoiding talking about decibels.
>> w1 = wgn(8192, 1, 10, 'real'); % generates real white noise, 8192 samples
>> w2 = wgn(8192, 1, 10, 'real');
>> mean(([w1 w2]).^2) % show mean powers of both noise signals
ans =
10.0410 10.0832
>> mean(([(w1+w1) (w1+w2)]).^2) % add one of them to itself, add both
ans =
40.1640 20.6295
So yes you do get a doubling of power when adding uncorrelated white-noise sources.. and when perfectly adding a single source, you quadruple the power. By definition the RMS amplitude is the root of the above.
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