Consider a particle on the real line with:
L=12(∂0q)2+f(q)∂0q
the equation of motion is that of a free particle ∂20q=0. In fact δ[f(q)∂0q]=0. Is this right?
I am studying Statics and saw that: The moment of a force about a given axis (or Torque) is defined by the equation: $M_X = (\vec r \times \...
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