Friday, October 10, 2014

quantum field theory - Simple QFT exercise


Consider a particle on the real line with:



$L=\frac{1}{2}(\partial_0q)^2 + f(q)\partial_0q$


the equation of motion is that of a free particle $\partial_0^2q=0$. In fact $\delta[f(q)\partial_0q]=0$. Is this right?




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