Saturday, October 25, 2014

The quantum state just after a position measurement


The wave function of a free particle is given as, $$\psi(x) ~=~ e^{-{ x }^{ 2 }/{ a }^{ 2 }}.$$


Then a position measurement is made and the position of the particle is found to be at $x=a$.


My question is: What is the state of the particle just after this measurement? Is it equal to $\psi (x=a)$ ?





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