The quantum state just after a position measurement

The wave function of a free particle is given as,

$$\psi(x) ~=~ e^{-{ x }^{ 2 }/{ a }^{ 2 }}.$$

Then a position measurement is made and the position of the particle is found to be at $x=a$.

My question is: What is the state of the particle just after this measurement? Is it equal to $\psi (x=a)$ ?