Tuesday, September 29, 2015

electromagnetism - What is wrong with this form of the Maxwell-Faraday equation?


What is wrong with this form of the Maxwell-Faraday equation?


$$\oint \vec{E}\ \partial \vec l= \bigcirc \hspace{-1.4em} \int \hspace{-.6em} \int \frac{\partial \vec B}{\partial t}$$


"Line integral of the electric field is equal to the double integral of partial derivative of magnetic field with respect to time".


So far as I remember the correct form used to be "Line integral of electric field is always (negative) surface integral of partially derived magnetic field..."




Answer



The integral form of the Maxwell-Faraday law is $$ \oint\limits_{\partial S} \mathbf{E} \cdot d\boldsymbol\ell = -\frac{d}{dt} \int\limits_S \mathbf{B} \cdot \hat{\mathbf{n}}\,da.$$ If you want to apply the time derivative to the integral on the RHS, you must account for two effects that can cause a change in the magnetic flux: the time derivative of the magnetic field, and the velocity $\mathbf{v}$ of the surface $S$ through the field. This gives $$ \oint\limits_{\partial S} \mathbf{E} \cdot d\boldsymbol\ell = -\int\limits_S \frac{\partial\mathbf{B}}{\partial t} \cdot \hat{\mathbf{n}}\,da\; - \oint\limits_{\partial S} \mathbf{B} \times \mathbf{v} \cdot d\boldsymbol\ell.$$ (See, e.g., Jackson 3rd edition, eq. 5.137.) You are correct that there must be a minus sign on the RHS; this is the mathematical statement of Lenz's law.


No comments:

Post a Comment

classical mechanics - Moment of a force about a given axis (Torque) - Scalar or vectorial?

I am studying Statics and saw that: The moment of a force about a given axis (or Torque) is defined by the equation: $M_X = (\vec r \times \...