Saturday, August 20, 2016

quantum mechanics - Conserved charges and generators


For the Klein Gordon field, the conserved charge for translation in space is given by: P=12d3kk{akak+akak}


If we were to find the generators for a space translation, we would find that, Pj=ij, where j=1,2,3.


If we act both of the above operators on the field ϕ, the result matches! My question is whether both of these, the generators and the conserved charges of a symmetry are always the same thing? What would be a simple way to see this connection?



Answer




OP is wondering whether the conserved charge associated to a continuous symmetry always generates the symmetry itself. We can say, in full generality, that the answer is


Yes.


Let us see how this works.


Classical mechanics.


We use a notation adapted to classical field theory rather than point-particle mechanics, but the former includes the latter as a special sub-case so we are losing no generality.


Consider a classical system which may or may not include gauge fields and/or Grassmann odd variables. For simplicity, we consider a flat space-time. Assume the system is invariant under the infinitesimal transformation ϕϕ+δϕ. According to Noether's theorem, there is a current jμ jμL˙ϕ,μδϕ which is conserved on-shell, μjμOS=0


This in turns implies that the associated Noether charge Q Q\overset{\mathrm{def}}=\int_{\mathbb R^{d-1}} j^{0}\,\mathrm d\boldsymbol x is conserved, \dot Q\overset{\mathrm{OS}}=0


In Ref.1 it is proved that the charge Q generates the transformation \delta\phi,



\delta\phi=(Q,\phi)




where (\cdot,\cdot) is the DeWitt-Peierls bracket. This is precisely our claim. The reader will find the proof of the theorem in the quoted reference, as well as a nice discussion about the significance of the result.


Furthermore, a similar statement holds when space-time is curved, but this requires the existence of a suitable Killing field (cf. this PSE post).


Moreover, for standard canonical systems, Ref.1 also proves that (\cdot,\cdot) agrees with the Poisson bracket \{\cdot,\cdot\}.


Quantum mechanics.


This is in fact a corollary of the previous case. Ref.1 proves that, up to the usual ordering ambiguities inherent to the quantisation procedure, the DeWitt-Peierls bracket of two fundamental fields agrees with the commutator [\cdot,\cdot] of the corresponding operators.


If we assume that the classical conservation law \partial_\mu j^\mu\equiv 0 is not violated by the regulator (i.e., if the symmetry is not anomalous), then we automatically obtain the quantum analogue of our previous result, to wit



\delta\phi=-i[Q,\phi]




as required.


References



  1. Bryce DeWitt, The Global Approach to Quantum Field Theory.


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