electrostatics - Electric field falls off faster than $frac{1}{r^2}$ for large distances

An excerpt from a book;

The electric field due to a charge configuration with total charge zero, is not zero; but for distances large compared to the size of the configuration, its field falls off faster than $\frac{1}{r^2}$ , typical of field due to a single charge. An electric dipole is the simplest example of this fact.

1. 
   

   Why is the field not zero even if the net charge is zero? Wouldn't the field cancel out?

   
   
   


2. 
   

   What does it mean by - the field falls off faster than $\frac{1}{r^2}$ for large distances.

   
   

Does it mean that the field intensity decreases at a faster rate at large distances? If yes, then why does that happen?

3. 
   

   Why is this typical of a field due to a single charge?

   
   



4. 
   

   How is the dipole an example of this fact?

   
   

I would appreciate if the answer is aimed for a highschool student with only basic knowledge of electrostatics and doesn't involve complicated equations.