I know we can find out the electric field using the electric field E=KQR2
taking small element dq and finding the electric field by integrating the value of dE over the circumference which will be E=kxQ√(a2+x2)3
where a is radius of ring and x is distance of point p on the axis of the ring. Can we find the same using the Gauss law?
No comments:
Post a Comment