Quantum electrodynamics based upon Euler-Heisenberg or Born-Infeld Lagrangians predict photons to move according to an effective metric which is dependent on the background electromagnetic field. In other words, photon trajectories are curved in presence of electromagnetic fields, meaning that an effective gravity is acting upon. If part of fermion masses is allegedly of electromagnetic origin, the question why their trajectories are not affected by this effective gravity naturally comes to mind.
Subscribe to:
Post Comments (Atom)
-
In the crystal, infinitesimal translational symmetry breaking makes the phonon, In ferromagnet, time-reversal symmetry breaking makes magnon...
-
A "Schrödinger's cat state" is a macroscopic superposition state. Quantum states can interfere in simple experiments (such as ...
-
The degeneracy for an $p$-dimensional quantum harmonic oscillator is given by [ 1 ] as $$g(n,p) = \frac{(n+p-1)!}{n!(p-1)!}$$ The $g$ is the...
No comments:
Post a Comment