Thursday, October 29, 2015

Doppler redshift in special relativity


I came across this exercise in Elementary General Relativity by Alan MacDonald:


A source of light pulses moves with speed v directly away from an observer at rest in an inertial frame. Let $ \Delta t_e $ be the time between the emission of pulses, and $ \Delta t_o $ be the time between their reception at the observer. Show that $ \Delta t_o = \Delta t_e + v\Delta t_e $.


Based on my understanding of special relativity, the space-time interval between two events as measured from two inertial frames of reference should be the same. Therefore, $$ \Delta t_e^2 = \Delta t_o^2 - \Delta x^2 $$ $$ \implies \Delta t_e^2 = \Delta t_o^2 - v^2\Delta t_o^2 $$ $$ \implies \Delta t_o = (1 - v^2)^{-1/2}\Delta t_e $$


which is not the same relation. What is wrong with my reasoning?



Answer



Your answer is right assuming $\Delta t_e$ is the interval between emission as measured by the emitting source itself. The given answer is right assuming $\Delta t_e$ is the time between emission as measured by the observer. It seems as though this problem is aiming at a lower level than your current understanding of relativity; you put too much thought into it.


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