The photoelectric experiment uses a setup like this:
The graph of photoelectric current I against potential applied at the anode/collecting plate V looks something like this:
Once we reach the saturation current, further increasing the collector potential V does not further increase the photoelectric current I. Rather, resistance simply increases (R=VI). But what is the underlying physical change in the electrodes that increases the resistance as V increases? Are there more negative charges on the cathode, inhibiting the current? Is that the reason why an increasing potential V causes R to increase?
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