While reading a text book about basics of Quantum Mechanics, I came across a situation in which it is said that
$E=\hbar\omega$ and also
$E = \frac12mv^2=p^2/2m$
where
$h$ Planck's constant
$\hbar=\frac{h}{2\pi}$ Planck's reduced constant
$\omega=2\pi f$ angular frequency
$m$ mass
$v$ velocity
$p$ momentum
But if I take the first definition,E=(h/2pi)*w,then
E=(h/2pi)*2*pi*f (because w=2*pi*f)
= h*f
= h*(v/λ) (because v=fλ)
= p*v (de-Broglie's wave-particle duality p=h/λ )
= mv*v (because p=m*v, the momentum)
E = m*v^2
This is not same as definition $E=\frac12mv^2$.
What am I missing in the derivation above?
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