Thursday, January 7, 2016

photons - Ejected Electrons with 0 KE?


So I was taught that:


Kinetic Energy (of electron) = Energy (of photon) - Ionization Energy


If E(photon) = IE, then KE=0 of the electron.


What does this physically/theoretically mean?



My current thoughts/interpretation is that enough energy/force is applied to ionize the electron so it is 'sufficiently far' from the atom, and then I guess it just moves with whatever speed it is moving at with natural kinetic laws, since no more energy/force is being applied....?


Any clarifications would be greatly appreciated, thanks in advance.




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