I am having trouble finding the eigenvalues for the Hamiltonian
H=P212M+P222m+K2x21+k2(x1−x2)2
Even though I can find a basis where the x1 and x2 coordinates are decoupled I then get products of momenta in my new Hamiltonian. I think this problem should be transformable into two decoupled oscillators. Am I wrong about that?
Answer
Structurally, it looks like this:
- Start by rescaling one or both of the position/momenta pairs such that the kinetic-energy term has both masses equal (while also retaining [xi,pi]=iℏ), and
- then find a rotation in the rescaled x1,x2 plane that will eliminate the coupling terms.
- That rigid rotation will be mirrored in the momentum plane, but because the masses are symmetric, it will no longer introduce momentum couplings.
Then you're done - you've got two decoupled oscillators whose position and momentum variables are canonically conjugate to each other and given as explicit linear combinations of the old ones.
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