Here's a part of the sequence:
(A)
(B)
(C)
(D)
(E)
1113122113
311311222113
...
The letters are the missing members (there are 5 missing members) and A is the first member of the sequence. The last member presented is not the end of the sequence, it can go on forever.
The sequence begins with a single integer. Can you tell which one? Simplest solution takes the cake.
Answer
3
13
1113
3113
132113
1113122113
311311222113
Bonus points:
The next in the series:
13211321322113
Unless I made a typo, I'm fairly certain this is all correct. It's the look and say sequence, where the next number describes the last;
1
11 (there's 1 1)
21 (there's 2 1s)
1211 (there's 1 2 and 1 1s)
So in other words, 3 is the first integer.
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