How to prove conservation of electric charge using Noether's first theorem according to classical (non-quantum) mechanics? I know the proof based on using Klein–Gordon field, but that derivation use quantum mechanics particularly.
Answer
By the word classical we will mean ℏ=0, and we will use the conventions of Ref. 1.
The Lagrangian density for Maxwell theory with various matter content is1
L = LMaxwell+Lmatter,
LMaxwell = −14FμνFμν,
Lmatter = LQEDmatter+LscalarQEDmatter+…,
LQEDmatter := ¯Ψ(iγμDμ−m)Ψ,
LscalarQEDmatter := −(Dμϕ)†Dμϕ−m2ϕ†ϕ−λ4(ϕ†ϕ)2,
with covariant derivative
Dμ = dμ−ieAμ,
(iγμDμ−m)Ψ m≈ 0,DμDμϕ m≈ m2ϕ+λ2ϕ†ϕ2,….
(The m≈ symbol means equality modulo matter eom, i.e. an on-shell equality.)
The infinitesimal global off-shell gauge transformation is
δAμ = 0,δΨ = −iϵΨ,δ¯Ψ = iϵ¯Ψ,
where the infinitesimal parameter ϵ does not depend on x.
The Noether current is the electric 4-current2
jμ = e¯ΨγμΨ−ie{ϕ†Dμϕ−(Dμϕ)†ϕ}+….
Noether's first Theorem is a theorem about classical field theory. It yields an on-shell continuity equation3
dμjμ m≈ 0.
Hence the electric charge
Q = ∫d3x j0
is conserved on-shell.
References:
- M. Srednicki, QFT.
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1 Note that the matter Lagrangian density Lmatter may depend on the gauge field Aμ
2 Interestingly, the electric 4-current jμ depends on the gauge potential Aμ in case of scalar QED matter.
3 Note that the above proof of the continuity equation (10) via Noether's first theorem (as OP requested) never uses Maxwell's equations.
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