In problem 3.35 of Griffiths' Introduction to electrodynamics, he states:
A solid sphere, radius R, is centered at the origin. The “northern” hemisphere carries a uniform charge density ρ0, and the “southern” hemisphere a uniform charge density −ρ0. Find the approximate field E(r,θ) for points far from the sphere (r \gg R).
The dipole moment is by definition
\textbf{p}=\iiint \textbf{r}'\rho(\textbf{r}') \;\mathrm{dV}
But Griffiths uses z=r'\cos \theta and says
\textbf{p}=\iiint \textbf{z}\rho(\textbf{r}') \;\mathrm{dV}
How does this work? Aren't you supposed to use r' in the integral?
In my calculations I get
\textbf{p}= \iiint_\text{northern hemisphere} \textbf{r}'\rho_0 \;\mathrm{dV} -\iiint_\text{southern hemisphere} \textbf{r}'\rho_0\;\mathrm{dV}
which gives \textbf{p}=0
when evaluated, which is wrong. Where have I setup my integral wrong?
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