Gauss divergence theorem for vectors can be easily explained by mass balance. But I can't think about one example for scalar gauss divergence theorem.
Gauss Divergence Theorem for scalars:
\int\limits_\Omega\nabla f(x)~\mathrm d\Omega=\int\limits_\Gamma f(x) \boldsymbol{n}~\mathrm d\Gamma,
Where:
f:\mathbb{\Omega}\to\mathbb{R},
\Omega is an open set, such that \Omega \subset \mathbb{R}^2 (or \mathbb{R}^3)
\Gamma is the boundary of \Omega and \boldsymbol n is the normal vector to \Gamma.
Answer
This theorem can be used to prove Archimede's Principle in a region with a non-uniform gravitational field.
The weight of the displaced fluid is \vec W=\int_\Omega \rho \vec g(\vec r)~\mathrm d\Omega. Let us consider a body fully immersed. Then the buoyancy force is given by \vec B=-\oint_\Gamma p(\vec r)~\mathrm d\vec \Gamma =-\int_\Omega\vec\nabla p~\mathrm d\Omega, where p(\vec r) is the pressure, d\vec \Gamma is the oriented area element and the given theorem is used.
A static fluid satisfy \vec\nabla p=\rho\vec g. Plugging this into the integral for \vec B and comparing with the integral for \vec W we see that the buoyancy force equals the weight of the displaced fluid even when the gravitational field is non-uniform.
Edit
Proof of the result claimed by the OP:
Consider a vector field f(x)\vec v, where f is a scalar field and \vec v is a constant non vanishing vector. By the divergence theorem: \oint_\Gamma f\vec v\cdot ~\mathrm d\vec \Gamma=\int_\Omega \vec\nabla\cdot (f\vec v)~\mathrm d\Omega. Since \vec\nabla (f\vec v)=\vec v\cdot\vec\nabla f, you get \vec v\cdot \oint_\Gamma f~\mathrm d\vec \Gamma=\vec v\cdot\int_\Omega\vec\nabla f~\mathrm d\Omega. Since this holds for any constant vector \vec v we get the result \oint_\Gamma f~\mathrm d\vec \Gamma=\int_\Omega\vec\nabla f~\mathrm d\Omega. In fact I have seen people calling this the "gradient theorem".
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