Monday, February 9, 2015

quantum mechanics - What is Deltat in the time-energy uncertainty principle?



In non-relativistic QM, the ΔE in the time-energy uncertainty principle is the limiting standard deviation of the set of energy measurements of n identically prepared systems as n goes to infinity. What does the Δt mean, since t is not even an observable?



Answer



Let a quantum system with Hamiltonian H be given. Suppose the system occupies a pure state |ψ(t) determined by the Hamiltonian evolution. For any observable Ω we use the shorthand Ω=ψ(t)|Ω|ψ(t).

One can show that (see eq. 3.72 in Griffiths QM) σHσΩ2|dΩdt|
where σH and σΩ are standard deviations σ2H=H2H2,σ2Ω=Ω2Ω2
and angled brackets mean expectation in |ψ(t). It follows that if we define ΔE=σH,Δt=σΩ|dΩ/dt|
then we obtain the desired uncertainty relation ΔEΔt2
It remains to interpret the quantity Δt. It tells you the approximate amount of time it takes for the expectation value of an observable to change by a standard deviation provided the system is in a pure state. To see this, note that if Δt is small, then in a time Δt we have |ΔΩ|=|t+ΔttdΩdtdt||dΩdtΔt|=|dΩdt|Δt=σΩ


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