Thursday, October 3, 2019

homework and exercises - How does the equation $1/I = r/E +R/E$ relate to $ y=mx+c$?



I have a graph of $1/$current against resistance, which is a straight line of positive gradient. I know that the gradient represents $1/V$ but I can't work out how the equation $1/I= r/E + R/E$ relates to $y=mx+c$. Could somebody please tell me what each part of $y=mx+c$ represents in relation to $1/I= r/E + R/E$?


Rearranged equation for Emf= IR + Ir





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