By electric or magnetic fields we mean the vector fields $\vec{E}(\vec{r},t)$ and $\vec{B}(\vec{r},t)$ respectively. But a gravitational field in Newtonian theory is a vector field that $\vec{g}(\vec{r})$ that obeys $\nabla\times\vec{g}=0$ and $\nabla\cdot\vec{g}=4\pi G\rho_{m}$. But in Einstein's theory we describe gravity as a tensor field $g_{\mu\nu}(x)$. How are these two descriptions of gravity, one in terms of the vector field $\vec{g}(\vec{r})$ and in other in terms of the tensor field $g_{\mu\nu}(x)$, compatible with each other in terms of the number of degrees of freedom? Thanks!
Subscribe to:
Post Comments (Atom)
classical mechanics - Moment of a force about a given axis (Torque) - Scalar or vectorial?
I am studying Statics and saw that: The moment of a force about a given axis (or Torque) is defined by the equation: $M_X = (\vec r \times \...
-
Consider a compound pendulum pivoted about a fixed horizontal axis, illustrated by the force diagram on the right: # Okay, I can't figur...
-
In the crystal, infinitesimal translational symmetry breaking makes the phonon, In ferromagnet, time-reversal symmetry breaking makes magnon...
-
I was solving the sample problems for my school's IQ society and there are some I don't get. Since all I get is a final score, I wan...
No comments:
Post a Comment